Question

A ball is thrown into the air with an upward velocity of 48 /. Its height ℎ in feet after seconds is given by the function ℎ = −162 + 48 + 9. How long does it take the ball to reach is the maximum height? What is the ball’s maximum height? Round to the nearest hundredth, if necessary.

please help

Answer 1

You need to proofread your post. Clearly you meant
h = −16t^2 + 48t + 9
it reaches its maximum height when v=0
v = 48-32t
Now you have t, so plug it in to find h

Answer 2

thank you so much

Answer 3

V = Vo + g*T = 0
48 + (-32)T = 0
T = 1.5 s.

Answer 4

its 4