Asked by aaaaaa
Three identical capacitors are connected so that their maximum equivalent
capacitance is 15 μF. There are three other ways to combine all three capacitors in a circuit. What is the total of the equivalent capacitances for each arrangement?
capacitance is 15 μF. There are three other ways to combine all three capacitors in a circuit. What is the total of the equivalent capacitances for each arrangement?
Answers
Answered by
oobleck
in parallel: C = C1 + C2 + C3
in series: 1/C = 1/C1 + 1/C2 + 1/C3
two in parallel: 1/C = 1/(C1+C2) + 1/C3
you can see what C1,C2,C3 must be, and then get the others.
in series: 1/C = 1/C1 + 1/C2 + 1/C3
two in parallel: 1/C = 1/(C1+C2) + 1/C3
you can see what C1,C2,C3 must be, and then get the others.
Answered by
oobleck
oh yeah. There is a 3rd way:
two in series, in parallel with the third.
C = C1 + 1/(1/C2 + 1/C3)
two in series, in parallel with the third.
C = C1 + 1/(1/C2 + 1/C3)
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