Asked by Anonymous
A pool is twice as long as it is wide. The pool takes up 12,168 square feet of the outdoor area at the YMCA. Find the dimensions of the pool.
Answers
Answered by
Reiny
width ----- x ft
length ---- 2x ft
x(2x) = 12168
2x^2 = 12168
divide both sides be 2, then take the square root
length ---- 2x ft
x(2x) = 12168
2x^2 = 12168
divide both sides be 2, then take the square root
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