Asked by Ryan

Euchre uses only 9’s, 10’s, Jacks, Queens, KIngs and aces. What is the probability that a 5 card hand will have either both red jacks or both black jacks?

Answers

Answered by oobleck
24 cards in all, so
P(both red) = P(both black) = 1/12 * 1/23
so, ...
Answered by Reiny
So there are only 24 cards
number of 5 card hands = C(24,5) = ...
number containing both red Jacks = C(22,3) = ...
number containing both black jacks = C(22,3) =
number of containing all 4 jacks = C(20,1) = ....

number containing either both 2 black or 2 red Jacks
= C(22,3) + C(22,3) - C(10,1) = ..... **

prob of your stated event = **/C(24,5) = ....
Answered by oobleck
Oops. Go with Reiny. My calculations were based on drawing only two cards.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions