a=0
b=3
such that E[Θ]=ax+b
E[Θ]=3 for all x therefore 0(x)+3=3 for all x
Suppose that the random variables Θ and X are not independent, but E[Θ∣X=x]=3 for all x . Then the LLMS estimator of Θ based on X is of the form aX+b , with
a=
b=
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