Question

A 25.0 mL sample of 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 ✕ 10-5) is titrated with 0.100 M KOH solution.
A) 8.0ml
B) 12.5 ml
C) 20.0 ml
D) 25.0 ml
E) 25.1 ml
F) 28.0 ml
bobpursley
and the question is? If it is the volume of KOH, then
NoralityAcid*VolumeAcid=NormalityBase*VolumeBAse
.1*25ml=.1*Vb
vb=25ml

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