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Bryan is making balloon arrangements. He has 8 blue balloons and 12 green balloons. What is the greatest amount of arrangements he can make if he wants them identical?
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Answered by
Reiny
HCF of 8 and 12 is 4
so he can make 4 same arrangements, each consisting of 2 reds and 3 greens
so he can make 4 same arrangements, each consisting of 2 reds and 3 greens
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