Ask a New Question

Question

What is the solubility of a 0.20 M solution of Zn(CN)2? (Ksp = 8.0 × 10–12)?
5 years ago

Answers

DrBob222
.....Zn(CN)2 ==> Zn^2+ + 2CN^-
I.......solid..............0............0
C......solid..............x.............2x
E.......solid..............x............2x

Ksp = 8E-12(Zn^2+)(CN^-)^2

Plug the E line into the Ksp expression and solve for x = (Zn^2+) = solubility Zn(CN)2
Post your work if you get stuck.
5 years ago

Related Questions

Solubility: Solubility of compounds in a)water (highly polar) b)methyl alchohol (intermediate pol... Which gas has solubility in water (at STP) of 3.39 L at 10.0°C? The solubility of a gas at 7.0 atm of pressure is 0.52 g/L . How many grams of the gas would be diso... What is the solubility (in g/L) of PbCl2 at 25 degree celsius? The solubility product of PbCl2 at... What is the solubility of Ca3(PO4)2 in 0.06 M of K3PO4 What is the solubility of Ca3(PO4)2 in 0.045 M of CaCl2 A certain gas has a solubility of .50 g/L under a pressure of 1500 torr. What would its solubility b... The solubility of Mn(OH)2 is 3.04 x 10^-4 gram per 100 ml of solution . A) write the balanced chem... The solubility of AB(s) in a 1.000-M solution of C(aq) is found to be 0.121 M. What is the Ksp of AB...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use