Asked by Striker

Find the density of a block that is less dense than water and held still 4.39 m underwater with a force of 0.855 N. When the object is in air, its weight is 0.585 N. (ANS: 406kg/m3)
Answered by R_scott
weight of water displaced by the block ... 0.855 N + 0.585 N = 1.44 N

weight of block / weight of water = .585 / 1.44 = .406

density of block = .406 * density of water
There are no AI answers yet. The ability to request AI answers is coming soon!