Asked by Striker
Find the density of a block that is less dense than water and held still 4.39 m underwater with a force of 0.855 N. When the object is in air, its weight is 0.585 N. (ANS: 406kg/m3)
Answers
Answered by
R_scott
weight of water displaced by the block ... 0.855 N + 0.585 N = 1.44 N
weight of block / weight of water = .585 / 1.44 = .406
density of block = .406 * density of water
weight of block / weight of water = .585 / 1.44 = .406
density of block = .406 * density of water
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