Asked by 3rfweaf
{3x-2y=10
{-1.5x+y=5
these are part of the same question i was wondering how the heck i solve this i have been stuck on this for hours and keeping getting dead ends and i cant you a graph.
{-1.5x+y=5
these are part of the same question i was wondering how the heck i solve this i have been stuck on this for hours and keeping getting dead ends and i cant you a graph.
Answers
Answered by
oobleck
since -1.5x + y = 5,
y = 1.5x + 5
Now substitute that into the 1st equation and you have
3x - 2(1.5x+5) = 10
3x - 3x - 10 = 10
-10 = 10
There is no solution to this. Thus, there are no solutions to the pair of equations.
Another way to look at is to note that if you miltiply the 2nd equation by -2, it becomes
3x - 2y = -10
But the first equation says that 3x-2y = 10
There is no way that 3x-2y can be both 10 and -10
y = 1.5x + 5
Now substitute that into the 1st equation and you have
3x - 2(1.5x+5) = 10
3x - 3x - 10 = 10
-10 = 10
There is no solution to this. Thus, there are no solutions to the pair of equations.
Another way to look at is to note that if you miltiply the 2nd equation by -2, it becomes
3x - 2y = -10
But the first equation says that 3x-2y = 10
There is no way that 3x-2y can be both 10 and -10
Answered by
3rfweaf
so wait would i just use the X and Y from 3x-2y=10?
Answered by
3rfweaf
OOOOOOOOOOOO wait i just got it nvm THANKS!!
Answered by
oobleck
good. The two lines are parallel, so they never meet. Thus, there is no intersection which could be the solution to both equations.
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