Question
i'm really lost here. please show me how to solve this
A 0.10 kg piece of copper at an initial temperature of 94 degrees C is dropped into 0.20 kg of water contained in a 0.28 kg aluminum calorimeter. The water and calorimeter are initially at 15 degrees C. What is the final temperature of the system when it reacher equilimbirum?
(Cp of Copper = 387J/kg * degC; Cp of Aluminum = 899 J/kg * degC; Cp of Water = 4186J/kg * degC)
thanks for any help
A 0.10 kg piece of copper at an initial temperature of 94 degrees C is dropped into 0.20 kg of water contained in a 0.28 kg aluminum calorimeter. The water and calorimeter are initially at 15 degrees C. What is the final temperature of the system when it reacher equilimbirum?
(Cp of Copper = 387J/kg * degC; Cp of Aluminum = 899 J/kg * degC; Cp of Water = 4186J/kg * degC)
thanks for any help
Answers
bobpursley
The sum of the heats gained in a closed system is zero.
masswater*cw*(Tf-Tiwater)+masscopper*Cc*(Tf-Ticopper)+massAl*Calum*(Tf-Tialum)=0
Put the numbers in, solve for Tf.
masswater*cw*(Tf-Tiwater)+masscopper*Cc*(Tf-Ticopper)+massAl*Calum*(Tf-Tialum)=0
Put the numbers in, solve for Tf.
ok thanks :)
hey what is the formula for cw,Cc, and Calum plss answer it plss
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