Asked by Kevin
                Evaluate the function below from x = 1 up to x = 4.
∫(7−lnx(x)(3+lnx))dx
            
        ∫(7−lnx(x)(3+lnx))dx
Answers
                    Answered by
            Reiny
            
    Suspicious of your typing, especially the lnx(x) part
Sent it to Wolfram and they read it as:
https://www.wolframalpha.com/input/?i=%E2%88%AB%287%E2%88%92lnx%28x%29%283%2Blnx%29%29dx+
https://www.wolframalpha.com/input/?i=%E2%88%AB%287%E2%88%92lnx%28x%29%283%2Blnx%29%29dx+%2C+from+1+to+4
Wolfram uses log for ln
    
Sent it to Wolfram and they read it as:
https://www.wolframalpha.com/input/?i=%E2%88%AB%287%E2%88%92lnx%28x%29%283%2Blnx%29%29dx+
https://www.wolframalpha.com/input/?i=%E2%88%AB%287%E2%88%92lnx%28x%29%283%2Blnx%29%29dx+%2C+from+1+to+4
Wolfram uses log for ln
                    Answered by
            oobleck
            
    To integrate lnx or x lnx, use integration by parts
u = lnx, du = 1/x dx
dv = dx, v = x
∫lnx dx = x lnx - ∫1/x * x dx = x lnx - x
If
u = lnx, du = 1/x dx
dv = x dx, v = 1/2 x^2
∫x lnx = 1/2 x^2 lnx - ∫1/2 x dx = 1/2 x^2 lnx - 1/4 x^2
    
u = lnx, du = 1/x dx
dv = dx, v = x
∫lnx dx = x lnx - ∫1/x * x dx = x lnx - x
If
u = lnx, du = 1/x dx
dv = x dx, v = 1/2 x^2
∫x lnx = 1/2 x^2 lnx - ∫1/2 x dx = 1/2 x^2 lnx - 1/4 x^2
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