Question
From a platform, an object is projected vertically into the air. Its height, metres above ground level after seconds, is modelled by the equation:
At what height above the ground is the platform from which the object was projected?
At what height above the ground is the platform from which the object was projected?
Answers
The equation is h= 3+20t-5t
Pls help me understand
at t = 0, the object is starting to be projected
plug in zero for t in the height equation to find the platform height
plug in zero for t in the height equation to find the platform height
That equation is incorrect, should be
h= 3+20t-5t^2 , where t is in seconds, and h is in metres
The steps suggested by R_scott are correct
h= 3+20t-5t^2 , where t is in seconds, and h is in metres
The steps suggested by R_scott are correct
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