Asked by Allie
Triangle ABC is given where m(angle)A=33 degrees, a=15 in., and the height, h, is 9 in. How many distinct triangles can be made with the given measurements? Explain your answer.
Answers
Answered by
Reiny
This is referred to as the "ambigious case"
From the given:
9/AC = sin33
AC = 9/sin33 = appr 16.5
now by the sine law sin(angle ABC) /16.5 = sin33/15
sin(angle ABC) = .6
angle ABC = 36.9° or angle ABC = 180-36.9 = 143.1°
So, two angles
both triangles can be drawn
From the given:
9/AC = sin33
AC = 9/sin33 = appr 16.5
now by the sine law sin(angle ABC) /16.5 = sin33/15
sin(angle ABC) = .6
angle ABC = 36.9° or angle ABC = 180-36.9 = 143.1°
So, two angles
both triangles can be drawn
Answered by
Allie
Thank you Reiny!
Answered by
Helping others is very precious
Is Reiny correct? Please someone tell me.
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