Asked by help please xx
Find the limit as t approaches infinity of
N=(K*1/2e^(rt-(3/16)rkt))/(1+(1/2)e^(rt-(3/16)))
N=(K*1/2e^(rt-(3/16)rkt))/(1+(1/2)e^(rt-(3/16)))
Answers
Answered by
oobleck
As t → ∞, e^-rt → 0 and e^rt → ∞
(K/2*0) / (1 + (1/2)∞) = 0
I suspect a typo, but maybe you can double-check.
(K/2*0) / (1 + (1/2)∞) = 0
I suspect a typo, but maybe you can double-check.