Asked by help please xx
                Find the limit as t approaches infinity of 
N=(K*1/2e^(rt-(3/16)rkt))/(1+(1/2)e^(rt-(3/16)))
            
            
        N=(K*1/2e^(rt-(3/16)rkt))/(1+(1/2)e^(rt-(3/16)))
Answers
                    Answered by
            oobleck
            
    As t → ∞,  e^-rt → 0 and e^rt → ∞
(K/2*0) / (1 + (1/2)∞) = 0
I suspect a typo, but maybe you can double-check.
    
(K/2*0) / (1 + (1/2)∞) = 0
I suspect a typo, but maybe you can double-check.
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