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a motorcycle is driven 50 km west then 30 km south and 25 km 30 degree west of south show the vector diagram find the total dis...Asked by Mary
a motorcycle is driven 50 km west then 30 km south and 25 km 30 degree west of south show the vector diagram find the total displacement of motorcycle
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Answered by
oobleck
draw the vectors and add them up. The final displacement vector is
<-50,0> + <0,-30> + <-25*0.5 , -25*√3/2>
<-50,0> + <0,-30> + <-25*0.5 , -25*√3/2>
Answered by
henry2,
All angles are measured CW from +y-axis.
Disp. = -50 - 30i + 25[210o] = -50 - 30i + 25*sin210 + (25*cos210)i
Disp. = -50-30i-12.5-21.7i = -62.5 - 51.7i = 81.1km[50.4o] W. of S.
Disp. = 81.1km[230.4o] CW.
Disp. = -50 - 30i + 25[210o] = -50 - 30i + 25*sin210 + (25*cos210)i
Disp. = -50-30i-12.5-21.7i = -62.5 - 51.7i = 81.1km[50.4o] W. of S.
Disp. = 81.1km[230.4o] CW.
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