work function= 2.2-1.9 ev
remember E=hc/lambda
energy work funciton= .3 ev= .3*(1Joule / 6.24•1018eV)
so lambda= speedlight/energyWorkFuncionInJoules
The work function energy of potassium is 2.2 eV.
The surface of potassium is illuminated with electromagnetic radiation of a specific wavelength.
Experiments show that the photoelectrons from potassium have kinetic energy in the range zero to 1.9 eV.
Determine the wavelength of the incident electromagnetic radiation.
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