The figure below shows a circuit with a 12.0-V battery connected to four resistors. How much power is delivered to each resistor? (Consider the following values: R1 = 1.35 Ω, R2 = 2.15 Ω, R3 = 3.95 Ω, R4 = 4.80 Ω.)

Question

The figure below shows a circuit with a 12.0-V battery connected to four resistors. How much power is delivered to each resistor? (Consider the following values: R1 = 1.35 Ω, R2 = 2.15 Ω, R3 = 3.95 Ω, R4 = 4.80 Ω.)

www.webassign.net/katzpse1/29-p-046-alt.png

👇

2 answers
(click or scroll down)

👇

Answer 1

oobleck answered
4 years ago

R3 and R4 combine to produce R such that

1/R = 1/3.95 + 1/4.80 = 2.17
So, the current through R1 and R2 is 12/2.17 = 5.53A

See what you can do with that. Either find the voltage across R3 and R4, or split the current between them.

Answer 2

Explain Bot answered
1 year ago

To calculate the power delivered to each resistor in this circuit, we can use the formula P = I^2 * R, where P is power, I is current, and R is the resistance.

To find the current flowing through the circuit, we need to use Ohm's law: V = I * R, where V is voltage, I is current, and R is resistance.

In this case, the voltage of the battery is 12.0 V. We need to find the total resistance of the circuit. Since the resistors are in series, the total resistance (R_total) is equal to the sum of the individual resistances: R_total = R1 + R2 + R3 + R4.

Plugging in the given values: R_total = 1.35 Ω + 2.15 Ω + 3.95 Ω + 4.80 Ω.

Now, we can use Ohm's Law to find the current (I): I = V / R_total.

Plugging in the values: I = 12.0 V / (1.35 Ω + 2.15 Ω + 3.95 Ω + 4.80 Ω).

Once we have the value of the current (I), we can calculate the power delivered to each resistor using the formula P = I^2 * R.

For example, for resistor R1: P1 = I^2 * R1.

Repeat this calculation for each resistor (R2, R3, R4) using the same formula.

Finally, you will have the power delivered to each resistor in the circuit.