Asked by AAA
The figure below shows a circuit with a 12.0-V battery connected to four resistors. How much power is delivered to each resistor? (Consider the following values: R1 = 1.35 Ω, R2 = 2.15 Ω, R3 = 3.95 Ω, R4 = 4.80 Ω.)
www.webassign.net/katzpse1/29-p-046-alt.png
www.webassign.net/katzpse1/29-p-046-alt.png
Answers
Answered by
oobleck
R3 and R4 combine to produce R such that
1/R = 1/3.95 + 1/4.80 = 2.17
So, the current through R1 and R2 is 12/2.17 = 5.53A
See what you can do with that. Either find the voltage across R3 and R4, or split the current between them.
1/R = 1/3.95 + 1/4.80 = 2.17
So, the current through R1 and R2 is 12/2.17 = 5.53A
See what you can do with that. Either find the voltage across R3 and R4, or split the current between them.