Question
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Assuming atmospheric pressure to be 1.01 * 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0m below the surface of the ocean?
thanks again:)
thanks
Assuming atmospheric pressure to be 1.01 * 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0m below the surface of the ocean?
thanks again:)
Answers
It is
Po + (sea water density)x g x(depth)
The units will be Pascals if density is in kg/m^3 and depth is in meters.
Po is the atmospheric pressure. g is the acceleration of gravity, 9.81 m/s^2
You should get about 2.52*10^5 Pa for your answer
Po + (sea water density)x g x(depth)
The units will be Pascals if density is in kg/m^3 and depth is in meters.
Po is the atmospheric pressure. g is the acceleration of gravity, 9.81 m/s^2
You should get about 2.52*10^5 Pa for your answer
thanks
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