Asked by Fiifi
find the third term of exponential sequence (G.p)
(√(2)-1),(3-2√(2),...
(√(2)-1),(3-2√(2),...
Answers
Answered by
oobleck
(3-2√2)/(√2-1)
= (3-2√2)/(√2-1) * (√2+1)/(√2+1)
= (3-2√2)(1+√2) / (2-1)
= 3+3√2-2√2-2√2√2
= 3 +√2 - 4
= √2 - 1
= (3-2√2)/(√2-1) * (√2+1)/(√2+1)
= (3-2√2)(1+√2) / (2-1)
= 3+3√2-2√2-2√2√2
= 3 +√2 - 4
= √2 - 1
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