Question
If 200 mL of 4.3500 M aqueous HCl reacts stoichiometrically according to the balanced equation, how many milliliters of 4.54 M aqueous NaCl are produced?
Na2CO3(aq) + 2HCl(aq) → CO2(g) + 2NaCl(aq) + H2O(l)
MM
HCl 36.461
NaCl 58.442
Na2CO3(aq) + 2HCl(aq) → CO2(g) + 2NaCl(aq) + H2O(l)
MM
HCl 36.461
NaCl 58.442
Answers
millimoles HCl = mL x M = ?
millimoles NaCl = millimoles HCl
millimoles NaCl = mL x M. You know millimoles NaCl and M, solve for mL. Post your work if you get stuck.
millimoles NaCl = millimoles HCl
millimoles NaCl = mL x M. You know millimoles NaCl and M, solve for mL. Post your work if you get stuck.
I THINK this answers the question you have tried to ask but let me point out that such answer doesn't mean anything. You already have a solution of HCl pf 200 mL so whavever you calculate for the NaCl doesn't mean anything.
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