Question

When a driver brakes an automobile, friction between the brakes disks and the brake pads converts part of the car’s kinetic energy that is transferred to the pads and disks by heat. During braking 192,000 J of energy is added to each wheel’s disk and brake pads, increasing temperature by 151 C. If the mass of each brake and it’s pass is 1760g. What is their specific heat?
energy = mass * specific heat * temperature change

192 kJ = 1.760 kg * s * 151ºC

solve for s

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