Asked by Tayler
When a driver brakes an automobile, friction between the brakes disks and the brake pads converts part of the car’s kinetic energy that is transferred to the pads and disks by heat. During braking 192,000 J of energy is added to each wheel’s disk and brake pads, increasing temperature by 151 C. If the mass of each brake and it’s pass is 1760g. What is their specific heat?
Answers
Answered by
R_scott
energy = mass * specific heat * temperature change
192 kJ = 1.760 kg * s * 151ºC
solve for s
192 kJ = 1.760 kg * s * 151ºC
solve for s
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