Asked by jerry
The partial pressure of water above a solution of water and a nonvolatile solute at 25oC is 19.2 mm Hg. What is the mole fraction of the solute
please help....I really don't know how I am supposed to solve this question.
I know that Partial pressure of the solvent above a soln = (mole fraction of solvent)(Vapor pressure above the pure solvent)
please help....I really don't know how I am supposed to solve this question.
I know that Partial pressure of the solvent above a soln = (mole fraction of solvent)(Vapor pressure above the pure solvent)
Answers
Answered by
DrBob222
Are you allowed to look up information OR do you have the normal vapor pressure of water at 25 degrees C in the problem?
Po H2O @ 25 degres C = 23.8 mm I believe but check me out on that. If it's listed in the problem use that value.
Then delta P = X(solute)*P(solvent)
delta P then is 23.8-19.2 = X(solute)*23.8 and you solve for X(solute).
Po H2O @ 25 degres C = 23.8 mm I believe but check me out on that. If it's listed in the problem use that value.
Then delta P = X(solute)*P(solvent)
delta P then is 23.8-19.2 = X(solute)*23.8 and you solve for X(solute).
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