Asked by ivy
Log√35 - log√7 + log√2
Answers
Answered by
Reiny
Log√35 - log√7 + log√2
= log (35)^(1/2) - log 7^(12) + log 2^(1/2)
= (1/2)log 35 - (1/2)log 7 + (1/2)log 2
= (1/2)(log 35 - log7 + log 2)
= (1/2)log(35/7*2)
= (1/2) log 10
= (1/2)(1)
= 1/2
= log (35)^(1/2) - log 7^(12) + log 2^(1/2)
= (1/2)log 35 - (1/2)log 7 + (1/2)log 2
= (1/2)(log 35 - log7 + log 2)
= (1/2)log(35/7*2)
= (1/2) log 10
= (1/2)(1)
= 1/2
Answered by
Khadijah
Log√35 × √2 ÷ √7
Log √70 ÷ √7
=√10
Log√10
=1÷2 log 10
1×1÷2×2
=1/2
Log √70 ÷ √7
=√10
Log√10
=1÷2 log 10
1×1÷2×2
=1/2
Answered by
Favor
Please help me solve log √35 base 10 - log √7 base 10 + log √12 base 10
Answered by
Favor
I still don't understand please explain
Answered by
OBIKA
I don't understand this maths
Answered by
Adeotan bukola
1/2
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