A roller coaster with a mass of 500.0 kg starts from a height of 27.0 meters with a speed of 5.2 m/s. It descends to a height of 2.00 meters before it starts back up. Some energy is loss to the work due to friction. The speed at the bottom of the ramp is 22.0 m/s. How much energy was lost to friction?

asked by Alex

5 years ago

841 views

0

0

1 answer

1/2 m v^2 + m g h - 1/2 m V^2

500 [(1/2 * 5.2^2) + (9.8 * 25) - (1/2 * 22)] ... Joules

answered by R_scott

0

0

Question

A roller coaster with a mass of 500.0 kg starts from a height of 27.0 meters with a speed of 5.2 m/s. It descends to a height of 2.00 meters before it starts back up. Some energy is loss to the work due to friction. The speed at the bottom of the ramp is 22.0 m/s. How much energy was lost to friction?

1 answer

1/2 m v^2 + m g h - 1/2 m V^2

500 [(1/2 * 5.2^2) + (9.8 * 25) - (1/2 * 22)] ... Joules

R_scott · Answer

1/2 m v^2 + m g h - 1/2 m V^2 500 [(1/2 * 5.2^2) + (9.8 * 25) - (1/2 * 22)] ... Joules