Asked by jill

how do you solve 27 - 3^5x * 9^x2
Answered by jill
sorry it is 27= 3^5x x 9^x2
Answered by R_scott
3^3 = 3^(5x) * [(3^2)^(x^2)] = 3^(2 x^2 + 5 x)

2 x^2 + 5 x - 3 = 0 ... (2 x - 1) (x + 3) = 0

x = 1/2 , x = -3
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