Asked by angel
A person applies a 13.5 N force to a hammer while it moves a distance of .12 m. The hammer completes 1.56 J of work on the nail. What is the efficiency of the hammer? Must show all work, have correct sig figs, and include correct units for full credit
Answers
Answered by
R_scott
work input = 13.5 N * .12 m = 1.6 J
efficiency = output / input = 1.56 J / 1.6 J
efficiency = output / input = 1.56 J / 1.6 J
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