Asked by Vince

The PMF of the random variable Y satisfies pY(−1)=1/6 , pY(2)=2/6 , pY(5)=3/6 , and pY(y)=0 for all other values y . The expected value of Y is:

E[Y]=

Answers

Answered by bao
not 3 frequency cant be negative
Answered by bao
i got the right answer its 3
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