Asked by Veronica

How many moles of oxygen gas must be in a 12.2 L container to exert a pressure of 0.877 atm at a temperature of 35.0°C (the ideal gas constant in this case is 0.0821 L atm / mole K)?
Please show work
Answered by DrBob222
Your old friend PV = nRT
That's the ideal gas law equation. Memorize that.
Answered by Veronica
@DrBob222
so how would I write out the equation?
Answered by DrBob222
It's PV = nRT
P = 0.877 atm
V = 12.2 L
n = ?
R = 0.0821 L*atm/mol*K
T = 273.15 + 35 = ?
Solve for n
Answered by Veronica
so its 0.57?
Answered by DrBob222
No, I don't get 0.57.
PV = nRT
n = PV/RT
n = 0.877*12.2/0.0821*308
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