Asked by jerry

The boiling point elevation of a solution consisting of 2.12 g of a nonvolatile solute in 97.4 g of benzene is 0.6602 oC. What is the molecular weight of the unknown solute?

i have no idea how to solve this question
Answered by DrBob222
delta T = Kf*molality
delta T = 0.660
Look up Kf for benzene (the freezing point depression constant for benzene which probably is in your text).
Calculate molality.
Then
Kg solvent x molality x molar mass = grams. Solve for molar mass.
Answered by jerry
thanks
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