Asked by vivian

A man drove his car north west for a distance of 10km,then east for 40km and then south for 60km.Calculate the overall displacement and direction of the car from the starting point.

Answers

Answered by oobleck
the final location is <-10/√2,10/√2> + <40,0> + <0,-60>
So, evaluate the (x,y) value and then
displacement is √(x^2+y^2)
and the angle θ has tanθ = y/x
Answered by henry2,
All angles are measured CW from +y-axis.
AD = AB+BC+CD = 10km[315o] + 40km[90o] + 60km[180o],
AD=(10*sin315+40*sin90+60*sin180)+(10*cos315+40*cos90+60*cos180)I
AD = 32.93 - 52.93i = 62.3km[31.9o] S. of E. = 62.3km[121.9o] CW.
= Displacement.
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