Asked by The orange baboon🦍.
Multiple each of the following and write the answers in standard form.
1.(1-4i)(-6+3i)
2. (1-3i)(1+3i)
1.(1-4i)(-6+3i)
2. (1-3i)(1+3i)
Answers
Answered by
Reiny
1.(1-4i)(-6+3i)
= -6 + 3i + 24i - 12i^2
= -6 + 27i + 12 , because i^2 = -1
= 6 + 27i
do #2 the same way
= -6 + 3i + 24i - 12i^2
= -6 + 27i + 12 , because i^2 = -1
= 6 + 27i
do #2 the same way
Answered by
oobleck
treat them like regular binomials, remembering that i^2 = -1
I'll do one, and then you can do any others in the same way.
(1-4i)(-6+3i)
= 1(-6+3i) - 4i(-6+3i)
= -6 + 3i + 24i - 12i^2
= -6 + 27i + 12
= 6 + 27i
You can always go to some site like wolframalpha.com to verify your answers. Just type it in and hit return.
I'll do one, and then you can do any others in the same way.
(1-4i)(-6+3i)
= 1(-6+3i) - 4i(-6+3i)
= -6 + 3i + 24i - 12i^2
= -6 + 27i + 12
= 6 + 27i
You can always go to some site like wolframalpha.com to verify your answers. Just type it in and hit return.
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