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A stone is thrown horizontal with a velocity of 40.0 m/s from a top of a building find its velocity and displacement after 3.00 seconds
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Answered by
oobleck
the horizontal speed is constant at 40 m/s, so the x di
The vertical position at time t is h - 4.9t^2, where h is the height of the building.
The vertical velocity is of course, -9.8t
So plug in t=3 and crank it out.
The vertical position at time t is h - 4.9t^2, where h is the height of the building.
The vertical velocity is of course, -9.8t
So plug in t=3 and crank it out.
Answered by
Divine marine abubo
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Answered by
Fiona
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