Question
Alli's ice cream shop offers 5 flavors and 10 toppings. Jali's ice cream shop offers 7 flavors and 7 toppings. Fernando's ice cream shop offers 9 flavors and 6 toppings. Laura's ice cream shop offers 13 flavors. If you want one flavor of ice cream and one topping, which shop gives you most options?
A Alli's
B Jali's
C Fernando's
D Laura's
A Alli's
B Jali's
C Fernando's
D Laura's
Answers
I am stuck between Fernando and Laura
flavors * toppings = options
thanks @R_scott !!
its c
hi is correct
so Fernando
fernando
Yes, that's correct. Fernando's ice cream shop offers the most options for choosing one flavor of ice cream and one topping, with a total of 54 options (9 flavors x 6 toppings = 54).
heyyy! bot, question
The probablity it will snow in the next two weeks is 1/12 this week, and 1/4 next week
What is P(snow this week, then snow next week)?
A-1/8
B-1/16
C-1/24
D-1/48
The probablity it will snow in the next two weeks is 1/12 this week, and 1/4 next week
What is P(snow this week, then snow next week)?
A-1/8
B-1/16
C-1/24
D-1/48
Using the multiplication rule for independent events, where the probability of both events happening is the product of their individual probabilities:
P(snow this week, then snow next week) = P(snow this week) x P(snow next week)
P(snow this week) = 1/12
P(snow next week) = 1/4
P(snow this week, then snow next week) = (1/12) x (1/4) = 1/48
Therefore, the answer is D, 1/48.
P(snow this week, then snow next week) = P(snow this week) x P(snow next week)
P(snow this week) = 1/12
P(snow next week) = 1/4
P(snow this week, then snow next week) = (1/12) x (1/4) = 1/48
Therefore, the answer is D, 1/48.
thank you!
You're welcome! If you have any more questions, feel free to ask.
also,,
how many different arrangements can be made with the letters from the word MATH??
how many different arrangements can be made with the letters from the word MATH??
The word MATH has 4 letters. Thus, there are 4 options for the first letter, 3 options for the second letter, 2 options for the third letter, and 1 option for the fourth letter.
Using the multiplication rule for counting, the total number of arrangements of the letters in MATH is:
4 x 3 x 2 x 1 = 24
So, there are 24 different arrangements that can be made with the letters from the word MATH.
Using the multiplication rule for counting, the total number of arrangements of the letters in MATH is:
4 x 3 x 2 x 1 = 24
So, there are 24 different arrangements that can be made with the letters from the word MATH.
Thanks again! also,
Ariel wants to choose 5 players for her basketball team. There are 7 players to choose from, how many different teams can she make?
Ariel wants to choose 5 players for her basketball team. There are 7 players to choose from, how many different teams can she make?
To count the number of different basketball teams Ariel can form, we can use the combination formula:
nCk = n! / (k! * (n-k)!)
where n is the total number of players (7 in this case), and k is the number of players to choose for each team (5 in this case).
So, the number of different basketball teams Ariel can form is:
7C5 = 7! / (5! * (7-5)!) = 21
Therefore, Ariel can form 21 different basketball teams.
nCk = n! / (k! * (n-k)!)
where n is the total number of players (7 in this case), and k is the number of players to choose for each team (5 in this case).
So, the number of different basketball teams Ariel can form is:
7C5 = 7! / (5! * (7-5)!) = 21
Therefore, Ariel can form 21 different basketball teams.
alright,,
How many different ways can a coach select the captain and co-captain of a team from a group of 20 people??
How many different ways can a coach select the captain and co-captain of a team from a group of 20 people??
The number of ways the coach can select a captain from 20 people is 20, since any one of the 20 people can be chosen as the captain.
After the captain is selected, there are only 19 people left to choose from for the co-captain position. Thus, the number of ways the coach can select the co-captain is 19.
Using the multiplication rule for counting, the total number of ways the coach can select the captain and co-captain of a team from a group of 20 people is:
20 x 19 = 380
Therefore, there are 380 different ways the coach can select the captain and co-captain of a team from a group of 20 people.
After the captain is selected, there are only 19 people left to choose from for the co-captain position. Thus, the number of ways the coach can select the co-captain is 19.
Using the multiplication rule for counting, the total number of ways the coach can select the captain and co-captain of a team from a group of 20 people is:
20 x 19 = 380
Therefore, there are 380 different ways the coach can select the captain and co-captain of a team from a group of 20 people.
okay! then,
There are 20 entries in the chess tournament. how many ways can the entries finish in first, second and third place??
There are 20 entries in the chess tournament. how many ways can the entries finish in first, second and third place??
To count the number of ways the 20 entries can finish in first, second, and third place, we will use the permutation formula:
nPk = n! / (n - k)!
where n is the total number of entries (20 in this case) and k is the number of places we are trying to fill (3 in this case).
So the number of ways we can fill 3 places out of 20 is:
20P3 = 20! / (20 - 3)! = 20 x 19 x 18 = 6840
Therefore, there are 6,840 ways the entries can finish in first, second, and third place.
nPk = n! / (n - k)!
where n is the total number of entries (20 in this case) and k is the number of places we are trying to fill (3 in this case).
So the number of ways we can fill 3 places out of 20 is:
20P3 = 20! / (20 - 3)! = 20 x 19 x 18 = 6840
Therefore, there are 6,840 ways the entries can finish in first, second, and third place.
Alright! again, tysm, ik your a bot but still ty! have a great day, thats all I needed! <3
You're very welcome! Don't hesitate to ask if you have any more questions in the future. Have a great day!