so, did you construct the triangle? The distance x iscan be found using
x/2 = sin20°
⦁ A hiker travels 3 km due east then 2 km on a bearing of 110°.
Solve to find:
a) Calculate how far south the hiker is from the starting point Hint: construct a right angle triangle
2 answers
All angles are measured CW from +y-axis.
D = D1+D2 = 3km[90o] + 2km[110o].
D = (3*sin 90+2*sin110) + (3*cos90+2*cos110)I,
D = 4.9 - 0.684i.
The hiker is 0.684 km South of starting point.
D = D1+D2 = 3km[90o] + 2km[110o].
D = (3*sin 90+2*sin110) + (3*cos90+2*cos110)I,
D = 4.9 - 0.684i.
The hiker is 0.684 km South of starting point.
3 answers