Asked by SOKARI
FROM A POINT ON THE EDGE OF THE SEA,ONE SHIP IS 5KM AWAY ON A BEARING SOUTH 50 DEGREES EAST AND ANOTHER IS 2KM AWAY ON A BEARING SOUTH 60 DEGREES WEST.HOW FAR APART ARE THE SHIPS?
Answers
Answered by
Reiny
It should be easy to see that the angle between them is 110 degrees.
Now it becomes a case for the cosine law.
Be careful with the sign of the -2(2)(5)cos 110 term in the equation.
Let me know what you get.
Now it becomes a case for the cosine law.
Be careful with the sign of the -2(2)(5)cos 110 term in the equation.
Let me know what you get.
Answered by
henry2,
All angles are measured CW from +y-axis.
Given: AB = 5km[130o], BA = 5km[130+180] = 5km[310o].
AC = 2km[240o].
BC = BA + AC = 5[310] + 2[240],
BC = (5*sin310+2*sin240) + (5*cos310+2*cos240)I,
BC = -5.56 + 2.21i = 5.98 km[-68.3o] = 5.98km[291.7o] CW.
The ships are 5.98 km apart.
Given: AB = 5km[130o], BA = 5km[130+180] = 5km[310o].
AC = 2km[240o].
BC = BA + AC = 5[310] + 2[240],
BC = (5*sin310+2*sin240) + (5*cos310+2*cos240)I,
BC = -5.56 + 2.21i = 5.98 km[-68.3o] = 5.98km[291.7o] CW.
The ships are 5.98 km apart.
Answered by
akinolabolaji
I want the drawing please
Answered by
Yolkers
STOP YELLING
Answered by
Anonymous
ABD BASIT
Answered by
smh
stop yelling
Answered by
TYOWUA
it is well solve the problem is NO drawing and this sign * l did not understand, but thanks you so- much.
Answered by
Muyideen
I don't know it teach me
Answered by
Bot
I apologize for any confusion. The sign I used, "*", is just a mathematical symbol for multiplication.
For the solution, we start by drawing a diagram. Let's say the point on the edge of the sea is called O. Then, we draw two lines from O to represent the positions of the ships A and B.
Next, we need to find the angles and distances. We are given that AO is 5km and makes an angle of 50 degrees with the south-east direction (or south 50 degrees east). This means that the angle AOB is 180 - 50 = 130 degrees (since the angles in a triangle add up to 180 degrees). We are also given that BO is 2km and makes an angle of 60 degrees with the south-west direction (or south 60 degrees west). This means that the angle ABO is 180 - 60 = 120 degrees.
Using the cosine law, we can find the distance AB between the ships:
AB^2 = 5^2 + 2^2 - 2(5)(2)cos(130)
AB^2 = 47.56
AB ≈ 6.89 km
Therefore, the distance between the ships is approximately 6.89 km.
I hope that helps!
For the solution, we start by drawing a diagram. Let's say the point on the edge of the sea is called O. Then, we draw two lines from O to represent the positions of the ships A and B.
Next, we need to find the angles and distances. We are given that AO is 5km and makes an angle of 50 degrees with the south-east direction (or south 50 degrees east). This means that the angle AOB is 180 - 50 = 130 degrees (since the angles in a triangle add up to 180 degrees). We are also given that BO is 2km and makes an angle of 60 degrees with the south-west direction (or south 60 degrees west). This means that the angle ABO is 180 - 60 = 120 degrees.
Using the cosine law, we can find the distance AB between the ships:
AB^2 = 5^2 + 2^2 - 2(5)(2)cos(130)
AB^2 = 47.56
AB ≈ 6.89 km
Therefore, the distance between the ships is approximately 6.89 km.
I hope that helps!
There are no AI answers yet. The ability to request AI answers is coming soon!