Asked by John
What is the parametrisation through the points (9,-2), (3,5)
Then Eliminate the parameter for the line
Then Eliminate the parameter for the line
Answers
Answered by
Reiny
parametrisation ???
slope or direction = -7/6 , I assume you know how I got that
(x,y) = (3,5) + t(6,-7)
parametric equation:
x = 3 + 6t ---> t = (x-3)/6
y = 5 - 7t ---> t = (y-5)/-7
(x-3)/6 = (y-5)/-7
6y - 30 = -7x + 21
7x + 6y = 51
slope or direction = -7/6 , I assume you know how I got that
(x,y) = (3,5) + t(6,-7)
parametric equation:
x = 3 + 6t ---> t = (x-3)/6
y = 5 - 7t ---> t = (y-5)/-7
(x-3)/6 = (y-5)/-7
6y - 30 = -7x + 21
7x + 6y = 51
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