Asked by Andrew

the sum of the first four terms is 26 and that of the next four terms is 74. find the values of (a) the first terms (b) the common difference.

Answers

Answered by Reiny
Assuming we have an AS
sum(4) = 26 ---> 2(2a + 3d) = 26
2a + 3d = 13

sum(8) = 26+74 =100 --> 4(2a + 7d) = 100
2a + 7d = 50

subtract : 4d = 37
d = 37/4
in 2a + 3d = 13
2a + 111/4 = 13
a = -59/8
Answered by Judith
Wonderful. Thanks
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