a triangle ABC, BC = 8cm, AC = 12cm and angle ABC = 120º.
Calculate the of AB, correct to one decimal place.
(b) If BC is the base of the triangle, calculate, correct to one decimal place:
(i) the perpendicular height of the triangle;
(ii) the area of the triangle;
(iii) the size angle ACB
3 answers
Have you drawn out the triangle as a start?
AB = 12 cos60º
(i) 12 sin60º
(ii) A = 1/2 * BC * (i)
(iii) sinC = (ii)/((i)+8)
(i) 12 sin60º
(ii) A = 1/2 * BC * (i)
(iii) sinC = (ii)/((i)+8)
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