Asked by jisung
two vertices of a parallelogram are a(2, 3) and b(8, 11), and the intersection of the diagonals is x(7, 6)
a. find the coordinates of the two other vertices. make sure to show all your work in finding the answer
b. explain what you had to do to find the answer. basically walking through how and why you did these things
a. find the coordinates of the two other vertices. make sure to show all your work in finding the answer
b. explain what you had to do to find the answer. basically walking through how and why you did these things
Answers
Answered by
oobleck
If the usual ordering is used, the A and B are ends of one side.
The diagonals bisect each other, so (7,6) is the midpoint of AC and BD.
So, to find (x,y) of C, you have
AC = X + (X-A)
(x,y) = (7,6) + (7-2,6-3) = (7,6)+(5,3) = (12,9)
Do the same to find D.
The diagonals bisect each other, so (7,6) is the midpoint of AC and BD.
So, to find (x,y) of C, you have
AC = X + (X-A)
(x,y) = (7,6) + (7-2,6-3) = (7,6)+(5,3) = (12,9)
Do the same to find D.
Answered by
R_scott
the diagonals of a parallelogram bisect each other
so the intersection is the midpoint between a given vertex and its opposite
so the intersection is the midpoint between a given vertex and its opposite