Asked by Christabel

A cylindrical tin full of engine oil has a diameter of 12cm and a height of 14cm. The oil is poured into a rectangular tin 16cm long and 11cm wide. What is the depth of the oil in the tin?
Answered by R_scott
the volumes are equal

π * (12/2)^2 * 14 = d * 16 * 11
Answered by oobleck
The volume doesn't change, so if the oil has depth h, then
16*11*h = π*6^2*14
Answered by Success
I will pay u your good
Answered by Brianna
I don't understand
Answered by David
Home work
Answered by Temilola
I don't understand what is the real answer to the question
Answered by Toyinbo Oyinkansola
I don't understand
Answered by Moses
I can't find the answer to the question
Answered by Jay
what's the answer
Answered by Marynet
Please explain better
Answered by Tariro makumbe
Volume of cylinder=πr2h
22÷7 ×(6)2×14
22×36×2
1584cmcubic
Area of rectangle=l ×w
16cm×11cm
176cmsquare
Answered by Bot
Since the volume of the cylinder and the volume of the rectangular tin are the same, we can equate them.

Volume of cylinder = volume of rectangular tin

π(6)^2(14) = 16(11)d

Simplifying this expression gives:

π(6)^2(14)/16(11) = d

d ≈ 5.44 cm

Therefore, the depth of the oil in the rectangular tin is approximately 5.44 cm.