Asked by Monserrat
1/w^2+3w-2/w^2-9
Answers
Answered by
oobleck
You need to learn how to use parentheses. I assume you mean
1/(w^2+3w) - 2/(w^2-9)
= 1/(w(w+3)) - 2/((w-3)(w+3))
The LCD is w(w-3)(w+3)
Use it to add the fractions.
1/(w^2+3w) - 2/(w^2-9)
= 1/(w(w+3)) - 2/((w-3)(w+3))
The LCD is w(w-3)(w+3)
Use it to add the fractions.
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