Asked by Imamu
In GP the Eleventh term is 128 times the fourth term,and the sum of second term and third term is 6. Find:
1) Common ratio.
2)Sum of the first five terms
1) Common ratio.
2)Sum of the first five terms
Answers
Answered by
Reiny
the Eleventh term is 128 times the fourth term
--> ar^10 = 128(ar^3)
divide by ar^3
r^7 = 128
r = 2 , so we already know the common ratio
the sum of second term and third term is 6
---> ar + ar^2 = 6
we know r, just complete to solve for a
--> ar^10 = 128(ar^3)
divide by ar^3
r^7 = 128
r = 2 , so we already know the common ratio
the sum of second term and third term is 6
---> ar + ar^2 = 6
we know r, just complete to solve for a
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.