Asked by Helen
Prove the divisibility of the following numbers:
12^8·9^12 by 6^16
12^8·9^12 by 6^16
Answers
Answered by
Reiny
12^8·9^12
= 3^8 * 4^8 * 3^24
= 3^32 * 2^16
= 3^16 * 2^16 * 3^16
= 6^16 * 3^16
which is clearly divisible by 6^16
= 3^8 * 4^8 * 3^24
= 3^32 * 2^16
= 3^16 * 2^16 * 3^16
= 6^16 * 3^16
which is clearly divisible by 6^16
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