Asked by Anonymous
12 cards with letters in the word INDEPENDENCE are put into a bag. Two cards are randomly selected. The first card selected is not replaced. Find the probability that both card show vowels.
Answers
Answered by
Reiny
I counted 5 vowels in the word,
Prob(both vowels) = (5/12)(4/11) =20/132
or
prob = C(5,2) / C(12,2) = 10/66 = 5/33
Prob(both vowels) = (5/12)(4/11) =20/132
or
prob = C(5,2) / C(12,2) = 10/66 = 5/33
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