Asked by John

A science teacher has a supply of 20% saline solution and a supply of 50% saline solution. How much of each solution should the teacher mix together to get 60 mL of 28% saline solution for an experiment?

I have an idea of what to do but need some help.
Answered by Reiny
let the amount of the 20% stuff be x ml
then the amount of the 50% stuff is 60-x ml

solve for x
.20x + .50(50-x) = .28(60)
20x + 50(60-x) = 28(60)
continue
Answered by Madyson
Can someone give me the answer I don't know anymore
Answered by Pepe The Frog
the answer is (c)16 mL of the 20% solution and the 16 mL of the 50% solution
Answered by Pepe The Frog
it isnt actuaaly c it will be (a) i think also i have ms tohmpson, im in 8th grade connexus, algebra 1 honors
-Caleb Bailey
Answered by Pepe The Frog
that answer is wrong sorry if anyone tried it i just got it wrong
Answered by robotic_squirrel
This is answers for honors algebra 1 i do not know if its the same for other ones

i got all but number 18 do not listen to pepe the frog
1.)d
2.)b
3.)c
4.)d
5.)c
6.)b
7.)a
8.)b
9.)b
10.)b
11.)b
12.)b
13.)d
14.)d
15.)b
16.)c
17.)c
18.)b i think
19.)b
20.)a
21.)a
22.)b
23.)d
24.)a
25.)d
Answered by robotic_squirrel
i am also pepe the frog i just wanted to help every one out
Answered by Pepe The Frog
I got a 24/25with the answers i put 96%
Answered by Big d
What is it then
Answered by Skittle-chan
oof, just use desmos and mathaway you'll be fine i got a 96 too
Answered by Beluga.
I got 13/26 from Robotic_Squirrel on standard algebra so only do his if your Honors
Answered by Oh my
The answer is 44mL os the solution 20% and 16mL of the 50%solution
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