Question
Fred goes down a 5.0-m slide at a playground in 2.0 s. He starts from rest and accelerates uniformly. Show that his acceleration while on the slide is 2.5 m/s2.
Answers
henry2,
d = 0.5*a*T^2.
5 = 0.5a*2^2,
a =
5 = 0.5a*2^2,
a =