Asked by J
A 5.0-kg block accelerates at 0.80 m/s2 along a horizontal surface when a forward horizontal 12.0-N force acts on it. Show that the force of friction on the block is 8.0 N
Answers
Answered by
henry2,
12-Ff = M*a.
12-Ff = 5*0.8.
Ff =
12-Ff = 5*0.8.
Ff =
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