Question
An ethylene glycol solution contains 30.2 g of ethylene glycol (C2H6O2) in 87.0 mL of water. (Assume a density of 1.00 g/mL for water.) FInd the freezing point and boiling point of the solution
Answers
DrBob222
dT = kf*m
mols ethylene glycol = grams/molar mass, then,
molality = mols ethylene glycol/kg H2O
Plug in above and solve for dT, subtract from zero C to obtain new freezing point.
Same for boiling point except, dT = Kb*molality. Find dT and add to 100 C to find new boiling point for H2O.
mols ethylene glycol = grams/molar mass, then,
molality = mols ethylene glycol/kg H2O
Plug in above and solve for dT, subtract from zero C to obtain new freezing point.
Same for boiling point except, dT = Kb*molality. Find dT and add to 100 C to find new boiling point for H2O.