Question
1. Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
y = ln(5x), y = 1, y = 3, x = 0; about the y-axis
2. Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the specified axis.
y = 32 − x2, y = x2; about x = 4
3. Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about y = 8.
64y = x3, y = 0, x = 8
4. A tank is full of water. Find the work required to pump the water out of the spout. Use the fact that water weighs 62.5 lb/ft3. (Assume a = 6 ft, b = 8 ft, and c = 12 ft.)
5.If 2.4 J of work are needed to stretch a spring from 9 cm to 13 cm and 4 J are needed to stretch it from 13 cm to 17 cm, what is the natural length of the spring?
y = ln(5x), y = 1, y = 3, x = 0; about the y-axis
2. Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the specified axis.
y = 32 − x2, y = x2; about x = 4
3. Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about y = 8.
64y = x3, y = 0, x = 8
4. A tank is full of water. Find the work required to pump the water out of the spout. Use the fact that water weighs 62.5 lb/ft3. (Assume a = 6 ft, b = 8 ft, and c = 12 ft.)
5.If 2.4 J of work are needed to stretch a spring from 9 cm to 13 cm and 4 J are needed to stretch it from 13 cm to 17 cm, what is the natural length of the spring?
Answers
another homework dump?
Looks like you need to show some work. I'll get you started.
#1. y = ln(5x), y = 1, y = 3, x = 0; about the y-axis
using shells of thickness dx,
v = 2(e/5) + ∫[e/5, (e/5)^3] 2πrh dx
where r = x and h=3-ln(5x)
using discs of thickness dy,
v = ∫[1,3] πr^2 dy
where r = x = e^(y/5)
#2.
v = ∫[-4,4] 2πrh dx
where r = 4-x and h = 32-x^2 - x^2
#3.
v = ∫[0,8] 2πrh dy
where r = 8-y and h = x = 4∛y
#4.
No idea what a,b,c are supposed to be. But, find where the center of mass is for the tank, and the work required is just weight * height_lifted
and the weight is the volume * density
#5.
work = 1/2 kx^2
where x is the distance stretched.
So, if the natural length is a, we have
k/2 ((13-a)^2 - (9-a)^2) = 2.4
k/2 ((17-a)^2 - (13-a)^2) = 4
Now divide and solve for a.
Looks like you need to show some work. I'll get you started.
#1. y = ln(5x), y = 1, y = 3, x = 0; about the y-axis
using shells of thickness dx,
v = 2(e/5) + ∫[e/5, (e/5)^3] 2πrh dx
where r = x and h=3-ln(5x)
using discs of thickness dy,
v = ∫[1,3] πr^2 dy
where r = x = e^(y/5)
#2.
v = ∫[-4,4] 2πrh dx
where r = 4-x and h = 32-x^2 - x^2
#3.
v = ∫[0,8] 2πrh dy
where r = 8-y and h = x = 4∛y
#4.
No idea what a,b,c are supposed to be. But, find where the center of mass is for the tank, and the work required is just weight * height_lifted
and the weight is the volume * density
#5.
work = 1/2 kx^2
where x is the distance stretched.
So, if the natural length is a, we have
k/2 ((13-a)^2 - (9-a)^2) = 2.4
k/2 ((17-a)^2 - (13-a)^2) = 4
Now divide and solve for a.
Oops. I'm sure you caught my error in #1.
v = π(e/5)^2(2 + ∫[e/5, (e/5)^3] 2πrh dx
v = π(e/5)^2(2 + ∫[e/5, (e/5)^3] 2πrh dx
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